##问题描述
>
Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
For example, this binary tree is symmetric:
1
/ \
2 2
/ \ / \
3 4 4 3
>
But the following is not:
1 / \ 2 2 \ \ 3 3
##C++ code
/**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool isSymmetric(TreeNode *root) {
TreeNode *left,*right;
if(root == NULL) return true;
queue<TreeNode *> q1,q2;
q1.push(root->left);
q2.push(root->right);
while(!q1.empty() && !q2.empty()){
left = q1.front();
q1.pop();
right = q2.front();
q2.pop();
if(left == NULL && right == NULL){
continue;
}
if(left == NULL || right == NULL){
return false;
}
q1.push(left->left);
q1.push(left->right);
q2.push(right->right);
q2.push(right->left);
}
return true;
}
}
##问题分析
该问题要利用一个队列存储节点